Posted 30.12.2020 by admin

Using Char In Dev C++

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Ok, so I am trying to write a program that will solve simple math and physics problems, and am trying to use strings and words more, so my question is:
is it possible to use a char in an if statement? I'm new to this so yeah. Here is what I tried and my compiler said 'NO' so does anyone know a way to get it to work?

Here's the code I have (just the part with the if statement):

and so on and so on but you prolly get the idea

Dev-C is a free IDE for Windows that uses either MinGW or TDM-GCC as underlying compiler. Originally released by Bloodshed Software, but abandoned in 2006, it has recently been forked by Orwell, including a choice of more recent compilers. DEV-C is a fully-featured integrated development environment (IDE) for creating, debugging and creating applications written in a popular C programming language. Even though tools for the development of C software have undergone countless upgrades over the years, a large number of developers located all around the world have expressed a wish to continue using DEV-C. Nov 20, 2017 A way to do this is to copy the contents of the string to char array. This can be done with the help of cstr and strcpy function. The cstr function is used to return a pointer to an array that contains a null terminated sequence of character representing the current value of the string.

Thanks in advance everyone!

Character classification in C is possible using functions specified in function library. Numerous function to classify characters are discussed in this article. Isalpha: This function returns true if character is an alphabet else returns false. All the characters from a.
Const moneypunct char, true &mpunct = usefacet char, true (loc); creates an object mpunct which is a reference to a moneypunct template class. This has information about the specified locale - in our case, the thousandssep method returns the character used for thousands separator.

C++ Char A

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Fbody682

Dev C++ Char

Here's the code I have (just the part with the if statement):

and so on and so on but you prolly get the idea

Thanks in advance everyone!

I'm guessing your intent is to compare to the string literal 'algebra' , but what you wrote is actually attempting to store the value stored in the variable called algebra to the variable called type . You need to add the quotes to make the compiler interpret it as a string literal and you need to use a double equal ( ) to execute an equality comparison, single equal is assignment. Even though, you can't compare a string literal to a character array.

I'd suggest converting it to an integer-driven menu rather than a string-driven one:

Edited by Fbody: n/a

The string class has been briefly introduced in an earlier chapter. It is a very powerful class to handle and manipulate strings of characters. However, because strings are, in fact, sequences of characters, we can represent them also as plain arrays of elements of a character type.
For example, the following array:
is an array that can store up to 20 elements of type char. It can be represented as:
Therefore, this array has a capacity to store sequences of up to 20 characters. But this capacity does not need to be fully exhausted: the array can also accommodate shorter sequences. For example, at some point in a program, either the sequence 'Hello' or the sequence 'Merry Christmas' can be stored in foo, since both would fit in a sequence with a capacity for 20 characters.
By convention, the end of strings represented in character sequences is signaled by a special character: the null character, whose literal value can be written as '0' (backslash, zero).
In this case, the array of 20 elements of type char called foo can be represented storing the character sequences 'Hello' and 'Merry Christmas' as:
Notice how after the content of the string itself, a null character ('0') has been added in order to indicate the end of the sequence. The panels in gray color represent char elements with undetermined values.

Initialization of null-terminated character sequences

Because arrays of characters are ordinary arrays, they follow the same rules as these. For example, to initialize an array of characters with some predetermined sequence of characters, we can do it just like any other array:

The above declares an array of 6 elements of type char initialized with the characters that form the word 'Hello' plus a null character'0' at the end.
But arrays of character elements have another way to be initialized: using string literals directly.
In the expressions used in some examples in previous chapters, string literals have already shown up several times. These are specified by enclosing the text between double quotes ('). For example:
This is a string literal, probably used in some earlier example.
Sequences of characters enclosed in double-quotes (') are literal constants. And their type is, in fact, a null-terminated array of characters. This means that string literals always have a null character ('0') automatically appended at the end.
Therefore, the array of char elements called myword can be initialized with a null-terminated sequence of characters by either one of these two statements:

In both cases, the array of characters myword is declared with a size of 6 elements of type char: the 5 characters that compose the word 'Hello', plus a final null character ('0'), which specifies the end of the sequence and that, in the second case, when using double quotes (') it is appended automatically.
Please notice that here we are talking about initializing an array of characters at the moment it is being declared, and not about assigning values to them later (once they have already been declared). In fact, because string literals are regular arrays, they have the same restrictions as these, and cannot be assigned values.
Expressions (once myword has already been declared as above), such as:
would not be valid, like neither would be:

This is because arrays cannot be assigned values. Note, though, that each of its elements can be assigned a value individually. For example, this would be correct:

Strings and null-terminated character sequences

Plain arrays with null-terminated sequences of characters are the typical types used in the C language to represent strings (that is why they are also known as C-strings). In C++, even though the standard library defines a specific type for strings (class string), still, plain arrays with null-terminated sequences of characters (C-strings) are a natural way of representing strings in the language; in fact, string literals still always produce null-terminated character sequences, and not string objects.
In the standard library, both representations for strings (C-strings and library strings) coexist, and most functions requiring strings are overloaded to support both.
For example, cin and cout support null-terminated sequences directly, allowing them to be directly extracted from cin or inserted into cout, just like strings. For example:

In this example, both arrays of characters using null-terminated sequences and strings are used. They are quite interchangeable in their use together with cin and cout, but there is a notable difference in their declarations: arrays have a fixed size that needs to be specified either implicit or explicitly when declared; question1 has a size of exactly 20 characters (including the terminating null-characters) and answer1 has a size of 80 characters; while strings are simply strings, no size is specified. This is due to the fact that strings have a dynamic size determined during runtime, while the size of arrays is determined on compilation, before the program runs.
In any case, null-terminated character sequences and strings are easily transformed from one another:
Null-terminated character sequences can be transformed into strings implicitly, and strings can be transformed into null-terminated character sequences by using either of string's member functions c_str or data:
(note: both c_str and data members of string are equivalent)

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